Question

functia logaritmica
${2}^{x2 - 6x - 2.5} = 16 \sqrt{2}$
Cine ma ajuta si pe mine va rog frumos la aceasta functie logaritmica ?​

Answer 1

Răspuns:

x=-1

x=7

Explicație pas cu pas:

$2^{\left(x^{2}-6x-2.5\right)}=16\sqrt{2}=>\\2^{\left(x^{2}-6x-2.5\right)}=2^{\frac{9}{2}}=>\\x^{2}-6x-2.5=\frac{9}{2}=>\\x^{2}-6x-\frac{5}{2}=\frac{9}{2}=>\\2x^{2}-12x-5=9=>\\2x^{2}-12x-5-9=0=>\\2x^{2}-12x-12=0=>\\x^{2}-6x-7=0=>\\x^{2}+x-7x-7=0=>\\x\left(x+1\right)-7\left(x+1\right)=0=>\\\left(x+1\right)\left(x-7\right)=0=>\\x+1=0;\ x-7=0=>\\x=-1;\ x=7$