Question

Gaseste 4 numere consecutive a caror suma imparita la 7 ne da catul 27 si trestul 5

Answer 1

(a+a+1+a+2+a+3):7=27 rest 5
a+a+1+a+2+a+3=27×7+5=189+5=194
3a+5=194
3a=194-6=189
a=189:3
a=63
a+1=64
a+2=65
a+3=66

a. /----/
a+1 /----/+1. suma 194
a+2/---/+2
a+3/---/+3

4 p+5=194
4 p=194-5
4 p=189
1 p=189:3
1 p=63