Question

Gaseste 4 numere consecutive a caror suma impartit la 7 ne da catul 27 iar restul 5 care se rezolva prin metoda figurativa

Answer 1

[a+(a+1)+(a+2)+(a+3)]:7=27 r 5
notam suma nr consecutive cu X
X:7=27 r 5
X=27·7+5=194
4a +6=194
4a=188
a=47
a+1=48
a+2=49
a+3=50