Question

gaseste 4 numere consecutive a caror suma impartita la 7 ne da catul 27 si restul 5.

Answer 1

a+a+1+a+2+a+3=4a+6
4a+6=7x27+5
4a+6=189+5
4a+6=194
4a=194-6
4a=188
a=188:4
a=47

nr sunt:
47,48,49,50

Answer 2

a : 7 = 27 rest 5
a = 7 x 27 + 5
a = 189 + 5
a = 194
suma celor 4 numere consecutive trebuie sa fie 194
a + b + c + d = 194
b = a+1
c = a + 2
d = a + 3
a + a +1 + a +2 + a +3 = 194
4a = 194 - 1-2-3
4a = 188
a = 188 : 4
a = 47
b = 48
c = 49
d = 50
verificam
47 + 48 + 49 +50 = 194