Question

gaseste numarul natural ... astfel incat 3/...<.../7<4/...
justifica raspunsul.

Answer 1

n∈N \ { 0 } ;
3 / n < n / 7 <=> 21 < $n^{2}$ <=> n∈{ 5, 6, 7, ....} ;
n / 7 < 4 / n<=> $n^{2}$ < 28 <=> n∈{ 1, 2, 3, 4, 5} ;
In final n = 5 .

Bafta !