Question

gaseste numerele a,b si c din


a:2+b+c:2=24
a+b:2+c:2=22
a:2+b:2+c=26

Answer 1

a/2+b+c/2=24
a+b/2+c/2=22
a/2+b/2+c=26
adunam membru cu membru
a/2+b+c/2+a+b/2+c/2+a/2+b/2+c=24+22+26
2a+2b+2c=72
a+b+c=36

a/2+b+c/2=24  ⇒a+2b+c=48  ⇒ b=48-(a+b+c)
a+b/2+c/2=22  ⇒2a+b+c=44  ⇒ a=44-(a+b+c) 
a/2+b/2+c=26  ⇒a+b+2c=52  ⇒ c=52-(a+b+c)

b=48-(a+b+c)=48-36=12
a=44-(a+b+c) =44-36=8
c=52-(a+b+c) =52-36=16