Question

gaseste numerele a,b si c din
a:2+b+c:2=24
a+b:2+c:2=22
a:2+b:2+c=26
VA ROG CINE MA POATE AJUTA!!!

Answer 1

a+2b+c=48, de unde a=48-2b-c
2a+b+c=44 
a+b+2c=52, deci 48-2b-c+b+2c=52 => c-b=4 => c=4+b
 a=48-2b-c => a=48-2b-4-b, adica a=44-3b
   avem: 2a+b+c=44
2(44-3b)+b+4+b=44
88-6b+2b+4=44
4b=48
b=12
Si acum avem: a=44-3b=44-3*12=44-36=8
c=4+b=4+12=16

Answer 2

a/2=b+c/2=24;
⇒a/2+2b/2+c/2=24
⇒a+2b+c=2·24
⇒a+2b+c=48;
a+b/2+c/2=22
⇒2a/2+b/2+c/2=22
⇒2a+b+c=2·22
⇒2a+b+c=44;
⇒a/2+b/2+c=26
⇒a/2+b/2+2c=26
⇒a+b+2c=2·26
⇒a+b+2c=52;
⇒metoda prin variante;