Question

gaseste numerele naturale mai mici decat 50 care impartite la 6 dau rest 2

Answer 1

d : 6 = c rest 2
catul <  9, deoarece 9 x 6 =54 > 50
catul < 8 , deoarece 8 x 6 + 2 = 50 care e egal , nu mai mic decat 50
catul = ( 0, 1, 2, 3, 4, 5, 6, 7)

Reconstituim impartirile:
d : 6 = 0 rest 2 ⇒ d = 0 x 6 + 2= 2
d : 6 = 1 rest 2 ⇒ d = 1 x 6 + 2 = 8
d : 6 = 2 rest 2 ⇒ d = 2 x 6 + 2 = 14
d : 6 = 3 rest 2 ⇒ d = 3 x 6 + 2 = 20
d : 6 = 4 rest 2 ⇒ d = 4 x 6 + 2 = 26
d : 6 = 5 rest 2 ⇒ d = 5 x 6 + 2 = 32
d : 6 = 6 rest 2 ⇒ d = 6 x 6 + 2 = 38
d : 6 = 7 rest 2 ⇒ d = 7 x 6 + 2 = 44

Raspuns:  2, 6, 14, 20, 26, 32, 38, 44