Question

gaseste valoarea lui y-(1+2+3...+48)=3 520

Answer 1

y-(1 +2+3+...+48)=3520
y-(48x49:2) =3520
y-(2352:2)=3520
y-1176=3520
y=3520+1176
y=4696
Am folosit formula:
1+2+3+...+n=n  x (n+1) :2

Answer 2

y - (1+2+3...+48) = 3.520

1+2+3...+48 = suma Gauss cu formula de calcul S=[n×(n+1)]:2

S = [48×{48+1)]: 2 = 1.176

y -1.176= 3.520

y = 3.520 + 1.176

y = 4.696