Question

gaseste valorile lui asfel incat relatile sa fie adevarate. 36 <4×9+a <41 a=......50> 5×9+a> 46. a=...

Answer 1

36 < 4*9 + a < 41
36 < 36 + a < 41
0 < a < 5
a ∈ (0, 5)

50 > 5*9 + a > 46
50 > 45 + a > 46
46 < 45 + a < 50
1 < a < 5
a ∈ (1, 5)

Answer 2

a) In primul rand facem inmultirile:
36 <36+a<41 dar in rescriem in felul urmator : 36< 36+a < 36 +5
deci a= {1,2,3,4}

b) facem acelasi lucru:

50> 45 +a> 46 apoi il rescriem invers 45+1< 45+a <45+5
deci a={2,3,4}