Question

Gasiti aria trapezului ABCD in care AB PARALEL CD,AB=6,CD=15 si h=4

Answer 1

a=(B+b)*h/2=(15+6)*4/2=21*4/2=84/2=42

Answer 2

ABCD = trapez
AB II CD,  AB = 6 cm, ( b)
 CD = 15 cm , ( B)
 h= 4 cm
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A trapez = ?
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A trapez = ( B + b ) x h totul supra 2
             = ( 15+6) x 4 supra 2, se face simplificarea cu 2
             = 21 x 2
             = 42 cm²