Question

gasiti media aritmetica a numerelor a=2(3+radical din 8) si b=6-4 radical din 2

Answer 1

(A+b)/2= [2(3+radical din8)+6-4radical din2] /2 = [2(3+radical din8)+2(3-2radical din2)]/2 = [2(3+2radical din2 +3-2radical din2)]/2= 6