Question

gasiti patru numere intregi consecutive care au suma -2

Answer 1

n+n+1+n+2+n+3=-2, 4n+6=-2, 4n=-8, n=-8/4=-2=primul numar

numerele vor fi : -2, -1, 0, 1

Answer 2

a + ( a + 1) + ( a + 2 ) + ( a + 3 ) = - 2

4 × a + 6 = - 2

4 × a = - 2 - 6

a = ( - 8 ) : 4

a = - 2 → primul numar

a + 1 = - 2 + 1 = - 1 → al doilea nr. consecutiv

a + 2 = - 2 + 2 = 0 → al treilea nr.

a + 3 = - 2 + 3 = 1 → al IV-lea nr. consecutiv

Verific: ( - 2) + ( - 1 ) + 0 + 1 = - 2 → suma celor 4 numere consecutive