Question

Gasiti prin substitutie ecuatiile care au solutia 1) 4 2)10

20+3t=100:2

Answer 1

$1)4$

$20 + 3 \times 4 = 100 \div 2$

$20 + 12 = 50$

$32 = 50 \: (F)$

$2)10$

$20 + 3 \times 10 = 100 \div 2$

$20 + 30 = 50$

$50 = 50 \: (A)$

$= > t = 10$