Matematică, întrebare adresată de pantera66628, 9 ani în urmă

Gasiți soluția pentru ecuațiile : a) 5(2x-3) +3(5x-6)+13=8(3x+7)-63
b) 7(4x-3)-4(3x+8)+25=3(4x+9)-43
c) 3(4x-5)-3(2x+7)+32=2(2x+1)-14
d) 6(x+3)+3x+2(2x+5)=3(x+1)-5
e) 3(2x-1)+4(x+2)-15=5(x+1)+35
f) 5(3x+4)+3(5x+6)-26=7(4x+9)-47

Răspunsuri la întrebare

Răspuns de CosmoteRo
2
a) 10x-15+15x-18+13=24x+56-63
10x+15x-24x=56-63+15+18-13
x=13
b).28x-21-12x-32+25=12x+27-43
28x-12x-12x=27-43+21+32-25
28x=12

x=12:28=0,42
c) 12x-15-6x-21+32=4x+2+14
12x-6x-4x=2+14+15+21-32
2x=20
x=10
d).6x+18+3x+4x+10=3x+3-5
6x+3x+4x-3x=3-5-10-18
10x=-30
x=-3
e)6x-3+4x+8-15=5x+5-35
6x+4x-5x=5-35+3-8+15
5x=-20
x=-4
f) 15x+20+15x+18-26=28x+63-47
15x+15x-28x=63-47-20-18+26
2x=4
x=2
Răspuns de moldcell20
1
a) 5(2x-3)+3(5x-6)+13=8(3x+7)-63=>10x-15+15x-18+13=24x+56-63=>
=>25x-20=24x-7=>25x-20-24x+7=0=>x-13=0=>x=13
b) 7(4x-3)-4(3x+8)+25=3(4x+9)-43=>28x-21-12x-32+25=12x+27-43=>
=>16x-28=12x-16=>16x-28-12x+16=0=>4x-12=0=>4x=12=>x=3
c) 3(4x-5)-3(2x+7)+32=2(2x+1)-14=>12x-15-6x-21+32=4x+2-14=>
=>6x-4=4x-12=>6x-4-4x+12=0=>2x+8=0=>2x=-8=>x=-8/2=>x=-4
d) 6(x+3)+3x+2(2x+5)=3(x+1)-5=>6x+18+3x+4x+10=3x+3-5=>
=>13x+28=3x-2=>13x+28-3x+2=0=>10x+30=0=>10x=-30=>x=-3
e)3(2x-1)+4(x+2)-15=5(x+1)+35=>6x-3+4x+8-15=5x+5+35=>
=>10x-10=5x+40=>10x-10-5x-40=0=>5x-50=0=>x=10
f) 5(3x+4)+3(5x+6)-26=7(4x+9)-47=15x+20+15x+18-26=28x+63-47=>
=>30x+12=28x+16=>30x+12-28x-16=0=>2x-4=0=>x=2
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