Question

Gasiti toate numerele de forma a b c stiind ca 721=a×100+b×10+1
-gasiti toate numerele de forma a b stiind ca suma lor e 9
-cate numere exista intre17 si 1017​

Answer 1

Răspuns:

ax100+bx10+1=721

ax100+bx10=721-1

ax100+bx10=720

7x100+2x10=720

a+b=9

a=7

b=2

$\frac{}{ab} = 72$

17...1017

(1017-17) :1+1

=1000:1+1

=1001