Question

Geometrie\\\\\\\\\\\\

Answer 1

Avem un triunghi isoscel deci:

AB=AC=BC/(2*cos30°)⇒AB=AC=BC/(2*√3/2)⇒

⇒AB=AC=BC√3/3⇒AB=AC=24√3/3⇒AB=AC=8√3(cm)

P=24+2*8√3=(24+16√3) cm

Raspuns: C) corect

Bafta!

Answer 2

m(∡B)=m(∡C)=30°=>ΔABC isoscel, AB=AC

Fie AD⊥BC, D∈(BC).

ΔABC e isoscel=>AD e inaltime si mediana=>BD=DC=BC/2=24 cm/2=12 cm

cos(∡ABD)=BD/AB

cos30°=√3/2

√3/2=12/AB=>AB=(12*2) cm/√3=24 cm/√3=24√3 cm/3=8√3 cm

AB=AC=8√3 cm

PΔABC=2AB+BC=2*8√3 cm+24 cm=24 cm+16 √3 cm=8(2√3+3) cm

C. 24+16√3