Question

Geometrie, clasa 6. Va rog frumooooos,, chiar am nevoie.....

Answer 1

AOC=AOB+BOC

AOC=54+29=83°

COD=AOD-AOC

COD=180-83=97°

COP=COD/2( COD supra 2)

COP=97/2= 48°30'

BOP=BOC+COP

BOP=29+48°30'= 77°30'

AOP=AOB+BOC+COP

AOP=54+29+48°30'=131°30'

BOD=BOC+COP+POD

POD= COD/2=> 48°30'

BOD=29°+48°30'+48°30'= 29°+97°=126°

Sper ca te-am ajutat!

Answer 2

Răspuns:

<COD=97

<COP=48°59`

<BOP=77°59`

<AOP=131°59°

< BOD=126°

Explicație pas cu pas:

AOD+BOC=AOC=>54°+29°=83°

AOD-AOC=COD=>180°-83°=97°

OP-bis.=>COP=POD=97°:2=48°59`

AOP=AOC+COP=83°+48°59`=131°59`

BOD=BOC+COD=29°+97°=126°

BOP=BOC+COP=29°+48°59`=77°59`