Question

geseste 4nr. consecutive a caror suma impartita la7 ne da catul 27 si restul 5

Answer 1

(a+b+c+d) :7 = 27 rest 5
(a+b+c+d)= 27×7 +5 = 189+5 = 194
a |____|
b |____|+1
c |____|+2
d |____|+3
avem 4 segmente egale +1+2+3 = 194
194 - 6 = 188
188: 4 = 47
a = 47
b = 47+1 = 48
c = 47+2 = 49
d = 47+3 = 50

Verificare:
47+48+49+50 = 194
Numerele consecutive sunt:
47; 48; 49; 50.