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a) -3a+5a-8a+13a-11a+4a= b) (2a+3b)-(4a-5b)-(-3a+4b)= c) 4√12a-5√27a+3√48a-3√3a=

Answer 1

a)-3a+5a-8a+13a-11a+4a=2a-8a+13a-11a+4a=-6a+13a-11a+4a=
=7a-11a+4a=-4a+4a=0
b)(2a+3b)-(4a-5b)-(-3a+4b)=2a+3b-4a+5b+3a-4b=2a-4a+3a+3b+5b-4b=
=-2a+3a+3b+5b-4b=a+8b-4b=a+4b
c)4√12a-5√27a+3√48a-3√3a=4+2√3a-5√27a+3√48a-3√3a=
=8√3a-5*3√3a+3*4√3a-3√3a=8√3a-15√3a+12√3a-3√3a=2√3a