Question

Gradina unei case are forma unui trapez dreptunghic ABCD ,ca i figura alaturata.
a) Aratati ca x=25
b) Fie E si F sunt mijloacele laturilor BC si AD .Calculati perimetrul figuri ABEF.
C) Determinati aria suprafetei gradinii
AVEM:
DC =x+2 metri
AD=15 metri
AB=2x-3 metri
CB= x metri
DC=x+2 metri
Va rog dati-mi o rezolvare detaliata va rooggg este urgent!!!!!
multumesc anticipat

Answer 1

a)Piciorul,perpendicularei,din,C,pe,AB,l-am,notat,cu,M.
Din,figura,stim,ca,CM=15,AM=DC=x+2
BM=(2x-3)-(x+2)=2x-3-x-2=>BM=x-5
Verificam,t.Pit.in,tr,dr,CMB
CM²+MB²=CB²
225+(x-5)²=x²
225+x²-10x+25=x²
-10x=-250
x=25(A)

b)EB=12,5
AB=(2x-3)=47
AF=7,5
Notam,EF∩CM=O
In,tr.dr.EOC,aflam,OE²=CE²-CO²=>OE²=156,25-56,25=>OE²=100=>OE=10
=>FE=FO+OE=27+10=37

Perim=47+12,5+37+7,5=104cm

c)Aria=(B+b)xh/2=(47+27)x15/2=74x15/2
Aria=555cm²