Question

Grupeaza convenabil termenii adunarilor de mai joc, pentru a calcula mai reppede. a) 1285+3001+1999+1715 b) 149+148+147+1351+1352+1353 c) 1101+3874+899+1126 d) 2888+387+1613+1222 P.S. Cred ca nu ma credeti pr....a!! :* :)))

Answer 1

1285+1715+3001+1999=3000+5000=8000 B)149+1351+148+1352+147+1353=1500+1500+1500=4500 C)1101+899+3874+1126=2000+5000=7000 D)2888+1222+387+1613=4110+2000=6110

Answer 2

a)1285+1715+3001+1999
   =3000+5000
   =8000
b)149+1351+148+1352+147+1353
   =1500+1500+1500
   =3000+1500
   =4500 
c)1101+899+3874+1126
   =2000+5000
   =7000
d)2888+1222+387+1613
   =4110+2000
   =6110

Sper Ca Te-am Ajutat! :D