Question

h)5-2^2 j)(4-2)^2 k)(4x3-10)^2 l)3^0-0^3+1^2004

Answer 1

5-2^2=5-4=1

(4-2)^2=2^2=4

(4×3-10)^2=(12-10)^2=2^2=4

3^0-0^3+1^2004=1-0+1=2