Question

H3PO4 : %H, %P,%O sa fie ca aici va rog repede azi

Answer 1

M(H3PO4)=3*1+1*31+4*16=3+31+64=98
1 mol corespunde 98 g
98 g H3PO4 contine 3 g H, 31 g P, 64 g O
100 g H3PO4 ---------x g H---y g P---z g O

98/100=3/x=31/y=64/z
x=3*100/98=3,06 % H
y=31*100/98=31,63 % P
z=64*100/98=65,31 % O