Question

haide rpd va rog mult​

Answer 1

a) (1/3 x-1/2)(1/3 x+1/2)=(x/3-1/2)(x/3 +1/2)= (x/3)² - (1/2)²=x²/9 - 1/4

c) (7x/5 + 3y/4)(7x/5 -3y/4= (7x/5)²-(3y/4)²= 49x²/25-9y²/16

e) (3√2x + 1/7)(3√2x - 1/7)= (3√2x)² - (1/7)²=18x² - 1/49

Answer 2

Răspuns:

(1\3x)^2-(1\2)^2= 1\9x^2-1\4

49\25x^2-9\16y^2

9√4x^2-1\49=9*2x^2-1\49=18x^2-1\49

Explicație pas cu pas:

Se aplica formula de calcul prescurtat (a+b) (a-b) =a2-b2