Question

Haideti!!!Cine ma ajuta?!!!

Answer 1

$1,7\ \textless \ x\ \textless \ 4,2$

$0,7\ \textless \ y\ \textless \ 2,5$
a)
 $dar : 1,4\ \textless \ 2y\ \textless \ 5$
⇒$1,7+1,4\ \textless \ x+2y \ \textless \ 4,2+5$
⇒$3,1\ \textless \ x+2y \ \textless \ 9,2$
b)
1,1x
$1,7*1,1\ \textless \ 1,1x\ \textless \ 4,2*1,1$
$1,87\ \textless \ 1,1x\ \textless \ 4,62$
0,2y

$0,7*0,2\ \textless \ 0,2y\ \textless \ 2,5*0,2$
$0,14\ \textless \ y\ \textless \ 0,5$
⇒$1,87+0,14\ \textless \ 1,1x+0,2y \ \textless \ 4,62+0,5$
⇒$2,01\ \textless \ 1,1x+0,2y \ \textless \ 5,12$