Question

Hei! Am nevoie de ajutor la acest exercitiu:a)Daca 2^x+1=128,atunci.....,adica...=>x=... b)Daca 3^2x+1=243,atunci...,adica.....=>x=........ c)Daca 2^x+2^x+1+2^x+2=448,atunci 2^x•(...+...+...)=.....=>x=

Answer 1

a)2ˣ⁺¹=128
128=2⁷
x+1=7 =>x=6

b)3²ˣ⁺¹=243
243=3⁵
2x+1=5 =>2x=4 =>x=2

c)2ˣ+2ˣ⁺¹+2ˣ⁺²=448
2ˣ·(1+2+2²)=448
2ˣ·7=448
2ˣ=448:7
2ˣ=64
64=2⁶ =>x=6