Question

hei! ce cantitate de hidrogen se obtine prin tratarea a 810g aluminiu cu acid clorhidric. va rog ajutati-ma!

Answer 1

2Al+6HCl=2AlCl3+3H2
Se da:
m(Al)=810g
m(H2)=?
Rezolvare:
M(Al)=27g/mol
v(Al)=m(Al)/M(Al)
v(Al)=810g/27g/mol=30mol
30 mol/2 mol=x mol/3 mol
x=(3*30)/2
x=45
v(H2)=45mol
M(H2)=2g/mol
m(H2)=M(H2)*v(H2)
m(H2)=2g/mol*45mol=90g
Raspuns: m(H2)=90g