Question

Help. 37+10-{600-2×[45+5×(380+28×12)]}=
Urgent ! Dau coroana

Answer 1

Răspuns: 6697

$37+10- \Big[600-2\cdot[45+5\cdot(380+28\cdot12)]\Big]=\\\\37+10- \Big[600-2\cdot[45+5\cdot(380+336)]\Big]=\\\\37+10- \Big[600-2\cdot(45+5\cdot716)\Big]=\\\\37+10- \Big[600-2\cdot(45+3580)\Big]=\\\\37+10- (600-2\cdot3625)=\\\\37+10- (600-7250)=\\\\37+10- 600+7250=\\\\\boxed{6697}$

Answer 2

Răspuns:

Explicație pas cu pas:

37 + 10 - { 600 - 2 × [ 45 + 5 × ( 380 + 28 × 12 )]} = 6 697

= 47 - { 600 - 2 × [ 45 + 5 × ( 380 + 336 )]}=

= 47 - [ 600 - 2 × ( 45 + 5 × 716 )] =

= 47 - [ 600 - 2 × ( 45 + 3 580 )] =

= 47 - ( 600 - 2 × 3 625 ) =

= 47 - ( 600 - 7 250 ) =

= 47 - ( - 6 650 ) =

= 47 + 6 650 =

= 6 697

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-> Am subliniat ordinea efectuarii operatiilor in exercitiul dat.

-> Rezolv mai intai operatiile din paranteza rotunda; desfintez paranteza rotunda, afland suma.

->  Paranteza dreapta o transform in paranteza rotunda, iar paranteza acolada o transform in paranteza dreapta.

->  Respect ordinea efectuarii operatiilor in exercitiul dat.

   Maria Denisia