Question

Help me!!exercitiul 5 :)

Answer 1

[tex] \left \{ {{3|x|+4y=1} \atop {4|x|+5y=2}} \right. \Leftrightarrow \left \{ {{12|x|+16y=4\ \atop {12|x|+15y=6}} \right. \\ y=4-6 =-2\\ Inlocuind:\\ 3|x|-8=1\\ 3|x|=9\\ |x|=3\Rightarrow x\in \{3,-3\}\\ S:(x,y)\in \{(3,-2),(-3,-2)\}[/tex]