Question

Help me please brooo​

Answer 1

Răspuns:

m,Mg= 30g

p=(100-6)%= 94%

a...-calculez masa de MgPUR

p= m,px100/m,i= 94x30/100g= 28,2g

-b....calcu;ez masa de MgO obtinuta, stiind A,Mg= 24g/mol   miuMgO=40g/mol

2x24gMg...........2x40gMgO

28,2gMg.................x

x=m=47gMgO

c...  c=mdx100/ms,unde ms=md+m,apa

solutia este formata din Mg(OH)2 dizolvat in restul de apa care ramane la sfarsitul reactiei

40g........18g..........58g

MgO + H2O---> Mg(OH)2

47g.............x..................y

y=m= 68,15g Mg(OH)2====> md

x= m=21,15gH2O

m,apa ramasa = 153-21,15=131,85g

ms= md+m,apa= 68,15+131,85=>200g

c= 68,15x100/200=>34%

daca consideri ca MgO nu reactioneaza cu apa

md= 47gMgO

ms= 47+153=> 200g

c= 47x100/200=>23,5%

Explicație: