Question

help me pls ( g, h, j, k) ​

Answer 1

Răspuns:

$(\sqrt{5}-2x)^{2} =5-4\sqrt{5}x +4x^{2} \\(\frac{1}{2} +x)^{2} =\frac{1}{4} + x+x^{2} \\(\frac{x^{2}}{3}-\frac{3}{2})^2=\frac{x^4}{9}-x^2+\frac{9}{4}\\(\frac{x}{5} -1,(6))^2=\frac{x^2}{25}-\frac{2x}{3}+\frac{4}{9}$

Explicație pas cu pas: