Question

Help me, va rog!!!!!!!

Answer 1

Salut,

$\left(\dfrac{2}3\cdot x\sqrt x\right)^{'}=\left(\dfrac{2}3\cdot x^{1+1/2}\right)^{'}=\left(\dfrac{2}3\cdot x^{3/2}\right)^{'}=\dfrac{2}3\cdot\dfrac{3}2\cdot x^{3/2-1}=x^{1/2}=\sqrt x.$

Ai înțeles ?

Green eyes.