Question

Help please urgent!!! Dau cel mai bun raspuns!!
a)determinati numarul natural n astfel incat 33a=21b si a supra b=n supra 44
b)Determinati numarul natural n astfel imcat 55a=5b si a supra b=n supra 66
VREAU REZOLVAREA COMPLETA VA ROG!! MULTUMESC ANTICIPAT!

Answer 1

a) 33a = 21b
a / b = n / 44  = > a = (b * n) / 44
Inlocuind pe a in prima relatie se obtine: 
(33 * b * n) / 44 = 21b
b se simplifica si ramane:
33n / 44 = 21
33n = 21 * 44
33n = 924
n = 924 / 33
n = 28

b) 55a = 5b
a / b = n / 66 => a = bn / 66
55bn / 66 = 5b
55n / 66 = 5
55n = 5 * 66
55n = 330
n = 330 / 55
n = 6

Answer 2

Miai scurt se poate face astfel:
[tex]a)...\;33a=21b \Leftrightarrow\;\frac{a}{b}=\frac{21}{33} \;\rightarrow\;\frac{21}{33}=\frac{n}{44}\\ deci\;n=\frac{21\cdot44}{33}=7\cdot4=28\;(am\; simplificat\;cu\;11\;apoi\;cu3\;\;)\\ b)...\;55a=5b\;\Leftrightarrow\;\frac{a}{b}=\frac{5}{55}=\frac{1}{11}\;\;\rightarrow\;\;\frac{1}{11}=\frac{n}{66}\;deci\;n=\frac{1\cdot66}{11}=6\;;[/tex]