Question

Help !!!! Toate 3 , a) , b) , c)
Dau coroana

Answer 1

 

[tex]\displaystyle\\ 6)\\ a)\\\\ \left(3\frac{1}{2}-\frac{1}{2} \right)+\left(1\frac{1}{3}-\frac{1}{3} \right)=3+1=\boxed{4}\\\\ b)\\\\ \frac{3}{14}\cdot \left(\frac{7}{8}\cdot\frac{8}{3}+3\frac{1}{3}\cdot 2\frac{1}{10} \right)=\\\\ =\frac{3}{14}\cdot \left(\frac{7}{3}+\frac{10}{3}\cdot \frac{21}{10}\right)= \\\\ =\frac{3}{14}\cdot \left(\frac{7}{3}+\frac{21}{3}\right)=\frac{3}{14}\cdot \frac{28}{3} = \frac{28}{14} =\boxed{2}[/tex]

[tex]\displaystyle\\ c)\\ 3:\left(2\frac{3}{4}-1\frac{15}{28}\right)+\frac{2}{3}: \frac{3}{2}=\\\\ =3:\left(\frac{11}{4}-\frac{43}{28}\right)+\frac{2}{3}: \frac{3}{2}=\\\\ =3:\left(\frac{77}{28}-\frac{43}{28}\right)+\frac{2}{3}\cdot \frac{2}{3}=\\\\ =3:\frac{34}{28}+\frac{2}{3}\cdot \frac{2}{3}=\\\\ =3\cdot \frac{24}{34}+\frac{2}{3}\cdot \frac{2}{3}=\\\\ =3\cdot \frac{12}{17}+\frac{2}{3}\cdot \frac{2}{3}=\\\\ =\frac{36}{17}+\frac{4}{9}= \\\\ =\frac{9\cdot 36}{9\cdot 17}+\frac{17\cdot 4}{17\cdot 9}=[/tex]

[tex]\displaystyle\\ =\frac{9\cdot 36}{9\cdot 17}+\frac{17\cdot 4}{17\cdot 9}= \\\\ =\frac{324}{153}+\frac{68}{153}= \boxed{\frac{392}{153}}[/tex]

Answer 2

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