Question

HELPPP MEEEEEEEEEEEE​

Answer 1

a=4√3 b=5√2

a=√4²·3 b=√5²·2

a=√16·3 b=√25·2

a=√48 b=√50→a<b

Answer 2

$\it 1) = \dfrac{2}{21}\cdot\dfrac{21}{4}-3\cdot\dfrac{6}{11}=\dfrac{1}{2}-\dfrac{11}{2}=-\dfrac{10}{2}=-5\\ \\ \\ 2)\ a=4\sqrt3\Rightarrow a^2=16\cdot3=48\\ \\ b=5\sqrt2\Rightarrow b^2=25\cdot2=50\\ \\ \\ 48<50\Rightarrow a^2<b^2 \Rightarrow a<b$

Remarcă:

a, b sunt numere pozitive.