Question

helpppp urgent!!!!!!​

Answer 1

2. ec tg in x0: y-f(x0)=f'(x0)(x-x0)

dar x0=2 => y-f(2) = f'(2)(x-2)

f(2)= 16-6+2=12

f'(x)= 6x^2 -3

f'(2)= 24-3= 21

ecuatia este y- 12= 21(x-2)

y-12=21x-42

21x-y-30=0

3. f'(x)= 6x^2 +12x+3

f"(x)= (f'(x))' = 12x+12

variabila x ia valori din intervalul [-1, infinit) doar pt valori pozitive a functiei 12x+12