Question

HEY !! MA AJUTATI SI PE MINE? Simplificati rapoartele si stabiliti domeniul lor de definitie: a) x^2 +8x+12 / x^2+5x-6 ; b) x^2+6x+8/ x^2-5x-14 .VA ROGGG SA LE FACETI FIECARE DESCOMPUS SEPARAT PLZ

Answer 1

a) (x² +8x+12) /(x²+5x-6) =(x+2)(x+6) /(x-1)(x+6)=(x+2)/(x-1)   {x∈R, x≠1}
x² +8x+12= x² +2x+6x+12=x(x+2)+6(x+2)=(x+2)(x+6)
x²+5x-6=x²-x+6x-6=x(x-1)+6(x-1)=(x-1)(x+6)


 b) (x²+6x+8)/( x²-5x-14)=(x+2)(x+4)/(x-7)(x+2)=(x+4)/(x-7)    {x∈R, x≠7}
x²+6x+8= x²+2x+4x+8=x(x+2)+4(x+2)=(x+2)(x+4)
 x²-5x-14= x²-7x+2x-14=x(x-7)+2(x-7)=(x-7)(x+2)