Question

Hidroxidul de natriu din 200 ml solutie 1 M a neutralizat 14,8 g acid monocarboxilic saturat. Acidul a fost?

Answer 1

Cm=md/M*Vs=>md=Cm*M*Vs=1*40*0.2=8g NaOH
n=m/M=8/40=0.2 moli NaOH
1 mol 1 mol
NaOH + CnH2nO2
0.2 mol. 0.2 mol
n=m/M =>M=m/n=14.8/0.2=74g/mol Aflu formula moleculara: 14n+32=74=>14n=42=>n=3. Formula acidului este C3H6O2. CH3-CH2-COOH; acid propanoic. Succes !