Question

How do i solve a quadratic equation were x is not equal to 1 ?
e.g, 3x( to the second power) + 5x( to the second power) + 29

Answer 1

rezolvare în mulțimea numerelor complexe:

$3{x}^{2} + 5{x}^{2} + 29 = 0$

$8 {x}^{2} = - 29$

${x}^{2} = - \dfrac{29}{8} \iff {x}^{2} = - \dfrac{58}{16}$

$x = \pm \dfrac{ \sqrt{58} }{4} i$