Question

I x plus 2 I - I x-3 I egal 2x-1.

Answer 1

1 caz
pentru x≥3 ecuatia devine x+2-(x-3)=2x-1
x+2-x+3=2x-1
2x=6
x=6:2
x=3 si x≥3 deci x=3 verifica ecuatia

al 2-lea caz
pentru x∈[-2; 3) ecuatia devine x+2-(3-x)=2x-1
x+2-3+x=2x-1
0=0 deci orice x∈[-2; 3) verifica ecuatia

al 3-lea caz
pentru x<-2, ecuatia devine -x-2-(3-x)=2x-1
-x-2-3+x=2x-1
2x=-4
x=(-4):2
x=-2 care nu apartine intervalului (-∞, -2)

deci solutia este x∈[-2;3]