Question

I27/10-18/5I=? -> aici e in modul
[4-(1/3)²] : 0,35=?

Answer 1

I27/10-18/5I = I -9/10 I = 9/10 = 0,9

[4-(1/3)²] : 0,35= (4-1/9):7/20 = 35/8*20/7 = 5/9*20 = 100/9

Answer 2

I27/10-18/5I=| 27/10 -2*18/5*2|=|27/10-36/10|=|(27-36)/10 |=|-9/10|=0,9
[4-(1/3)²] : 0,35=(9*4/9-1/9): 35/100=(36-1)/9 : 35/100= 35/9 * 100/35= 1/9 * 100/1= 100/9=11,(1)