Question

iar urmatorul exercitiu este:daca a+b=4 si c=5,calculati:a)5a+3c+5b;b)10a-2c+10b;c)(4a+c+4b)x[3c-(2a+2b)].multumesc frumos!

Answer 1

daca a+b=4 si c=5,calculati:

a)5a+3c+5b =5(a+b)+3c=5*4+3*5=5(4+3)=5*7=35

b)10a-2c+10b=10(a+b)-2c=10*4-2*5=40-10=30

c)(4a+c+4b) x [3c-(2a+2b)] =
=[4(a+b)+c] x[3c-2(a+b)] =
=(4x4+5) x (3x5-2x4)=
=(16+5) x (15-8)=
=21x7=147