Question

Identifica hidrocarbura stiind ca 4,928L(c.n) formeaza prin combustie 29,04g CO2,iar 0,16 moli reprezinta 6,4g.

Answer 1

-deduc masa molara a hidrocarburii
n=m/M
0,16=6,4/m----> M= 40g/mol

-deduc moli C din hidrocarbura
n,hidroc= V/Vm=> n= 4,928l/22,4l/mol=0,22mol
nCO2=nC= 29,04g/44g/mol= 0,66mol

0,22 mol.hidrocarbura ...............0,66 molCo2(=molC)
 1mol.............................................................x
x=3molC

-hidrocarbura poate fi : C3H8, C3H6, C3H4
C3H4   are masa molara 40g/mol !!!!