Question

Identifica hidrocarbura stiind ca 4,928L formeaza prin combustie 29,04g Co2, iar 0,16 moli reprezintă 6,4 g?

Answer 1

notez hidrocarbura CxHy

0,16mol............6,4g

1mol..................M= 40g/mol

niu,CxHy= V/Vm= 0,22mol

niu.CO2= m/M= 29,04/44= 0,66 mol Co2

1mol CxHy, prin ardere, formeaza     x,molCO2 si y/2 molH2O

0,22mol..CxHy.................................0,22x molCO2

dar O,22X=0,66----> x=3

M= 12x+ y---> 40= 36+y====> y= 4molH----> C3H4   propina