Question

Îmi calculati si mie compozitia procentuala a urm. Substanțe CaCo3 CaO CH4 MgCI2

Answer 1

 M CaCO3= 40+12+3*16=100g/mol
In 100g CaCO3..............40gCa.......12gC.......48gO
     100g CaCO3.............xgCa...........yg C........zgO
x=100*40 / 100=40% Ca
y=100*12 / 100=12%C
z=100*48 / 100=48%O

M CaO= 40+16=56g/mol
In 56gCaO................40g Ca.......16gO
   100g CaO.............xg Ca..........ygO
x=100*40 / 56=71,42% Ca
y=100*16 / 56= 28,57% O

M CH4=12+4*1=16g/mol
In 16g CH4.............12gC...........4gH
    100gCH4............xgC..............ygH
x-100*12 / 16=75%C
y=100*4 / 16=25%H

MMgCl2=24+2*35,5=95g/mol
In 95gMgCl2..............24gMg............71gCl
  100gMgCl2..............xgMg..............ygCl
x=100*24 / 95=25,26%Mg
y=100*71 / 95=74,73%Cl