Question

Imi poate calcula cineva asta?

Answer 1

b= (√5+√3-2)²- 2(√15-2√5)+ √48+1

b= (√5+√3-2)²- 2(√15-2√5)+ 4√3+1

b= √5²+2×√5×√3-2+ (√3-2)² - 2√15- 4√5+ 4√3+ 1

b= 5+ 2√15- 2+ √3²- 2×√3×2+ 2²- 2√15- 4√5+ 4√3+ 1

b=5+ 2√15- 2+ 3- 4√3+ 4- 2√15- 4√5+ 4√3+ 1

b=5- 2+ 3+ 4- 4√5+ 1

b=5+ 4- 4√5+1

b=9- 4√5+ 1

b= 10- 4√5