Question

Imi poate explica cineva cum se factorizeaza niste expresii cum ar fi : (x^2-2x-8)/(x^2-4x-12)

Answer 1

$\frac{x^{2}-2x-8}{x^{2}-4x-12}=\\ \\=\frac{x^{2}+2x-4x-8}{x^{2}+2x-6x-12}$

= [x(x+2)-4(x+2)] / [x(x+2)-6(x+2)]

= (x+2)(x-4) / (x+2)(x-6)

= (x-4) / (x-6)