Question

Imi poate rezolva cineva astea ? Am nevoie la Matematica astazi ( doar ce este incercuit )

Answer 1

pe prima pagina nu e nimic incercuit. pe a doua e ceva taiat. iata ce e taiat:
1.(x-2+2)/3x=x/3x=1/3
2. x^4/4y² · 4y²/x³=x (am simplificat in cruce, impartirea la o fractie e inmultit cu inversul fractiei)
3. (x+1)²/2(x²-1) · 2x/(x+1)= (x+1)²/2(x+1)(x-1) · 2x/(x+1)=
= (x+1)/2(x-1) · 2x/(x+1)= x/(x-1)
4. (10-x²+15)/3x=(25-x²)/3x=(5-x)(5+x)/3x
5. (x-2)(x+2)/(x+2)² · x(x+2)/x(x-2)= (x-2)/(x+2) · (x+2)/(x-2)=1
6. E(x)=[x²-(x+1)²-1]/x(x+1)= (x²-x²-2x-1-1)/x(x+1)=-2(x²+x+1)/x(x+1)