Question

imi puteti descompune in factori urmatoarele ecuatii
(2x-3)^2-(x+6)^2
4x^3-4x^2-x+1
x^2+11x+18

Answer 1

(2x-3)^2-(x+6)^2=
(2x-3)-(x+6)•(2x-3+x+6)=
(2x-3-x-6)•(3x+3)=
(x-9)•3(x+1)


4x^3-4x^2-x+1=
4x^2•(x-1)-(x-1)=
(4x^2-1)•(x-1)=
(2x-1)•(2x+1)•(x-1)

x^2+11x+18=
x^2+9x+2x+18=
x•(x+9)+2(x+9)=
(x+2)•(x+9)